For Geeks & Brainiacs #09- Tightly Packed -
There are three gift boxes: a small cube-shaped box, a sphere-shaped box, and a large cube-shaped box.
The small cube-shaped box has a volume of 3,375 cm³
. If the small
box is placed inside the sphere-shaped box, it's a perfect fit. And if the sphere-shaped box is placed
inside the large
cube-shaped box, it's also a perfect fit.
Ignoring the thickness of the walls of the boxes, can you find the volume of the large cube-shaped box?
: You will need to use Pythagoras' theorem to help you find the length of the longest side
(c) of a triangle with a right angle (90°): a²
: To find the diameter of the sphere-shaped box, you must find the distance that separates
the two opposing corners of the small cubical box (i.e. the space diagonal
: 17,535.47 cm³.
: Because the small cube-shaped box is a perfect fit inside the sphere-shaped box, its
corners will touch the inside of the sphere-shaped box. Therefore, the diagonal of the small cube-shaped
box from one corner to its opposing corner (termed the space diagonal
correspond to the diameter of the sphere-shaped box. This is represented in the image below by line y,
which is the distance between opposing corners A and B. Since the small cube-shaped box has a volume of
3,375 cm³, each side has a length of 15 cm (cube root of 3,375).
Using Pythagoras' theorem, we can determine the length of x
15² + 15² = x²
x = 21.21 cm
Now that we have x
, we can determine y
15² + 21.21² = y²
y = 25.98 cm (the diameter of the sphere-shaped box).
Since the sphere-shaped box is a perfect fit inside the large cube-shaped box, its diameter represents the
length of each side of the large cube-shaped box. The volume of the large cube-shaped box is therefore:
25.98³ = 17,535.47 cm³
Do you have a suggestion
for this puzzle (e.g. something that should
be mentioned/clarified in the question or solution, bug, typo, etc.)?